r loop through multiple columns
Pass in some of your "looping" variables, and just do an if check at the beginning. Also, thanks to akrun for the test data. How to match words in 2 list against another string of words without sub-string matching in Python? Let's see a few examples. I'll leave that to you. v1 <- c('ard','b','','','','rr','','fr','','','','','gh','d'); ind <-... Change the panel.margin argument to panel.margin = unit(c(-0.5,0-0.5,0), "lines"). It is not uncommon to wish to run an analysis in R in which one analysis step is repeated with a different variable each time. I would create a list of all your matrices using mget and ls (and some regex expression according to the names of your matrices) and then modify them all at once using lapply and colnames<- and rownames<- replacement functions. It, by default, doesn't return no matches though. ... A matrix has 2-dimension, rows and columns. dx1 = ix2 + v1 + v2 + v3. You will learn how to use the following functions: pull(): Extract column values as a vector. it's better to generate all the column data at once and then throw it into a data.frame. This should get you headed in the right direction, but be sure to check out the examples pointed out by @Jaap in the comments. Dataframe.columns returns a sequence of column names. It can be also used to remove columns from the data frame. r,paste,assign,names. Otherwise... You can try cSplit library(splitstackshape) setnames(cSplit(mergedDf, 'PROD_CODE', ','), paste0('X',1:4))[] # X1 X2 X3 X4 #1: PRD0900033 PRD0900135 PRD0900220 PRD0900709 #2: PRD0900097 PRD0900550 NA NA #3: PRD0900121 NA NA NA #4: PRD0900353 NA NA NA #5: PRD0900547 PRD0900614 NA NA Or using the devel version of data.table i.e. This is easy to do in Excel but I wonder if there's. The correlation matrix, corr, is in your workspace. Tag: r,loops. An Introduction To Loops in R. According to the R base manual, among the control flow commands, the loop constructs are for, while and repeat, with the additional clauses break and next.. You can do this with something like: get_scalar <- function(name, FUN=max) { sapply(mydata[,name], function(x) if(all(x == -999)) NA else FUN(as.numeric(x[x != -999]))) } Note that I've changed your function... Use [[ or [ if you want to subset by string names, not $. Would actually love to see both if possible. End If. Now, we can apply the following R code to loop over our data frame rows: for( i in 1: nrow ( data2)) { # for-loop over rows data2 [ i, ] <- data2 [ i, ] - 100 } for (i in 1:nrow (data2)) { # for-loop over rows data2 [i, ] <- data2 [i, ] - 100 } The i++ is using post increment, so the value of the expression i++ is what the value was in the variable i before the increment. If Range("E" & i).Value > 0.99 Then Range("O" & i).Value = 1
3 $\begingroup$ I have a dataframe with columns as defined below. You can alternatively look at the 'Large memory and out-of-memory data' section of the High Perfomance Computing task view in R. Packages designed for out-of-memory processes such as ff may help you. Now, how can we get the columns from the cursor result separately. R queries related to “loop through columns dataframe” loop over column names python df; iterate through specific column pandas; python loop through all columns in dataframe; python loop through data frame column; how to iterate over a column values in dataframe python; pandas looping on a col; how to loop through the column a a dataframe Here's another possible data.table solution library(data.table) setDT(df1)[, list(Value = c("uncensored", "censored"), Time = c(Time[match("uncensored", Value)], Time[(.N - match("uncensored", rev(Value))) + 2L])), by = ID] # ID Value Time # 1: 1 uncensored 3 # 2: 1 censored 5 # 3: 2 uncensored 2 # 4: 2 censored 5 Or similarly,... You can do it with rJava package. that with a for-loop in R. 20.1 For-Loop basics The command below will run the loop 10 times (i in 1:10) and reproduce the command inside the loop: for (i in 1:10) { print(i) } #Your output will be numbers 1 through 10. Your sapply call is applying fun across all values of x, when you really want it to be applying across all values of i. Dim x As Long, r As Range
Method #1: Using DataFrame.iteritems(): Dataframe class provides a member function iteritems() which gives an iterator that can be utilized to iterate over all the columns of a data frame. As there were 3 columns so 3 tuples were returned during iteration. I would like to loop through a list of dataframes and change the column names (I want each of the columns to have the same name) Does anyone have a solution using the following data? How to innerHTML a function with array as parameter? $\begingroup$ a function that takes the columns of a dataframe that I give as an input and maps the new values onto old values,just in those columns ,is what I'm trying to figure out ,without using loops .we can do something like it with "Purrr" package,but not sure how to . Either using a for loop or apply? In linux, you could use awk with fread or it can be piped with read.table. [on hold], How to split a text into two meaningful words in R. It should satisfy the following: The outer loop should be over the rows of corr. volumes = c(1.6, 3, 8) for (i in 1:length(volumes)) { mass <- 2.65 * volumes[i] ^ 0.9 print(mass) } One option would be to make your function(response) recursive. Construct a for loop As in many other programming languages, you repeat an action for […] varA + col2*covAB + col5*covAB + col2*col5*varB. Often, the easiest way to list these variable names is as strings. plotHistFunc <- … How to group by multiple columns in dataframe using R and do aggregate function. ; Fill in the nested for loop! This tutorial will walk you through a simple loop of columns in a row. Here is a sneak peak of the output, which we will generate from this basic loop macro in Excel using Visual Basic for Applications. R: Using the “names” function on a dataset created within a loop. Remove quotes to use result as dataset name, Fitting a subset model with just one lag, using R package FitAR, How to plot data points at particular location in a map in R, Subsetting rows by passing an argument to a function, How to quickly read a large txt data file (5GB) into R(RStudio) (Centrino 2 P8600, 4Gb RAM), Rbind in variable row size not giving NA's, IllegalStateException: Iterator already obtained [duplicate], Calling function and passing arguments multiple times, ggplot2 & facet_wrap - eliminate vertical distance between facets, how to get values from selectInput with shiny, performance issues executing list of stored procedures. Example 2 illustrates how to import multiple CSV files using a for-loop in R. First, we have to use the list.files function to extract all file names in our folder: data_files <- list.files("C:/Users/Joach/Desktop/My Folder") # Identify file names data_files # Print file names # "data1.csv" "data2.csv" "data3.csv". 21.3 For loop variations. Application.run "sub1". The problem is that you pass the condition as a string and not as a real condition, so R can't evaluate it when you want it to. How can I iterate through nested HTML lists without returning the “youngest” children? A better approach would be to read the files into a list of data.frames, instead of one data.frame object per file. In this example, we have to multiply two different columns by a very long number and then add 10. Dec 6, 2020 #1 Hi, I'm trying to do a check against a few thousand rows to see if they contain the information within a column header - … For every column in the Dataframe it returns an iterator to the tuple containing the column name and its contents as series. I have a dataset with more than two columns and want to write a loop that allows me to compare the values of an entire column to the those of another column. We may want to put this in a function so that we don’t have to worry about typing the number multiple times and ending up with typos like we did above. ; The print statement should print the names of the current column and row, and also print their correlation. I have provided one set of example, similar to this I have many countries with loan amount and gender variables If Range("O5").Value > Date Then
VBA to loop through multiple columns. Dim v As Variant
I would like to loop through a list of dataframes and change the column names (I want each of the columns to have the same name) Does anyone have a solution using the following data? varA + col2*covAB + col4*covAB + col2*col4*varB. Javascript: Forloop Difference between i++ and (i+1), Highlighting specific ranges on a Graph in R. Sleep Shiny WebApp to let it refresh… Any alternative?